Solves with the name Ann

 A lot of coups in the family tree have been people with the name of Ann:

Ann Gibson born 1836 Northumberland. I was not the solver, but it transpired she was visiting her previously unknown mother in the year 1861 accompanied by her two eldest children. Very helpful. Solve: census

Ann Morgan born 1761 Glamorgan. Her unmarried daughter's estate duty papers from 1859, a hundred years later, lead me to the will of Ann's sister Mrs Pengilly and from that we can reconstruct Ann's whole family tree. Solve: IR27 series

Ann Phillips born 1797 Glamorgan. She was Ann Morgan's great-niece. It looked like she possibly left Wales for Utah in the 1850s. The key document here was her second marriage certificate which confirmed all the relationships. Solve: certificate

Ann Thomas born 1817 Glamorgan. She presumably left her husband and family in Wales and sailed for Utah in the 1860s to join her daughter. This was from the 1871 census which showed her absent and later 'dead'. Comparing DNA test results for Utah- and Wales- based descendants confirmed this. Solve: AncestryDNA

Ann Hooper born 1839 Somerset. She is in the 1861 census with her mother, but what next was a mystery. We found her marriage in Bristol 1866 to Mr Penny. And then a surprise remarriage in Wincanton 1869 to Mr Read. I think the method was combing the 1881 census for her birthplace. Solve: census

Ann Perry born 1761 Cornwall. She married age 19 to Mr Jennings and I had no idea where she was from. Looking again at the witnesses, I noticed a chap called Thomas Rogers. This little clue was enough to work out he was Ann's stepfather. And thus piece the whole thing together. Solve: CornwallOPC

Ann Shaw born about 1773 Derbyshire. She married age 16-18 to Mr Gee died the following year and I had no real idea where she was from. Though I had a couple of guesses. Her widower possibly remarried a cousin and the clinching evidence was William Shaw's administration from 1815 that seemed to link together the two families. Pending further proof. Solve: LichfieldAdministrations